Question

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 green crayons. A crayon is selected, replaced, and then another is selected. Find the probability: P (yellow and red) .

Answer 1

Answer:

P(yellow the red) =  $\frac{3}{32}$

Step-by-step explanation:

P(yellow and red) = P(yellow then red) + P(red then yellow)

P(yellow then red) = $\frac{6}{32} . \frac{8}{32} = \frac{3}{64}$

P(red then yellow) = P(yellow then red)

P(yellow and red) = $\frac{3}{64} + \frac{3}{64} = \frac{3}{32}$