Statement 1: 2AB = AC
Reason 1: Given
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Statement 2: AC = AB+BC
Reason 2: Segment addition postulate (which your teacher abbreviated to "Seg + Post")
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Statement 3: 2AB = AB+BC
Reason 3: Substitution
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Statement 4: 2AB-AB = AB+BC-AB
Reason 4: Subtraction Property of Equality
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Statement 5: AB = BC
Reason 5: Combine like terms
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Notes:
- The first reason is "given" since we just simply restate what the instructions provide. If you are given multiple items, you list each one at a time.
- The segment addition postulate is where we break a line into smaller parts and then build it back together.
- Substitution is simply replacement. We've replaced AC with 2AB.
- The subtraction property of equality is the idea where we subtract the same thing from both sides. In statement 4, we're subtracting AB from both sides.
- The last statement of any proof is always the thing we're trying to prove. Once we reach such a statement, there's no need to go any further since the proof has concluded.
Answer:
The probability of choosing an A student is 58% (0.58 or 29/50)
Step-by-step explanation:
The fact that 23 students are boys and 27 are girls is irrelevant to the question so we can ignore that.
There are 50 students in all and out of these students 15 boys and 14 girls made an A.
We can first add 15+14 which equals 29. So 29 students out of 50 made in A on the exam.
29/50 equals 0.58 or 58%.
I would say 60 cause 10% of 90 is 9 which is a difference of 81 while 10% of 60 is 6 which is a difference of 54.
Answer:
17
8/17
Step-by-step explanation:
x=
sin∠D = 
