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frutty [35]
3 years ago
10

On a map, 9 cm represents 15 miles. If the distance between two cities on the map is 15 cm, how many miles separate the cities?

Mathematics
1 answer:
torisob [31]3 years ago
4 0

Answer:

15 cm on the map is equal to 25 miles.

Step-by-step explanation:

Given that,

On a map, 9 cm represents 15 miles.

The distance between two cities is 15 cm. We need to find the distance in miles.

9 cm = 15 miles

1\ cm=\dfrac{15}{9}\ \miles

So, 15 cm is equal to,

15\ cm=\dfrac{15}{9}\times 15\ miles\\\\=25\ miles

So, 15 cm on the map is equal to 25 miles.

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12 muffins can be made.

Step-by-step explanation:

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3 years ago
In the rectangle ABDF above, C and E are midpoints of sides line ED and line DF, respectively, what fraction of the areas of the
aivan3 [116]

Answer:

Is shaded 5/8 of the area of the rectangle

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of triangle ABC represent 1/4 of the total area

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(1/4)(1)+(1/8)(3)=(1/4)+(3/8)=(2/8)+(3/8)=5/8

therefore

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Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.
hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the  length of the unknown side (PR)

q² = p² +  r² - 2prCos Q

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p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² -  2* 33*67 Cos 19°

    = 1089 + 4489 - 4422 * 0.95

     = 1089 + 4489 - 4200.9

    = 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}

Sin P = 0.3

P = Sin^{-1} 0.3\\

P = 17.5°

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Solve each expression if x=-0.25 and y= -6
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Answer:

i don't know

Step-by-step explanation:

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3 years ago
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6.12 x 3=18.36
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