A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz
The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz
2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz
3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz
B) The answers are:
the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz
The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz
2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz
3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
Answer:
Step-by-step explanation:
Domain of a function is a set of x-values (input values) for which the function is defined.
Range of a function is a set of y-values (output values) for the given set of input values.
7). Domain → (-∞, ∞)
Range → (-∞, ∞)
8). Domain → (-∞, ∞)
Range → [-2, ∞)
9). Domain → [-2, 2]
Range → [-3, 3]
10). Domain → (-∞, ∞)
Range → [-1, 1]
There are 23 square green blocks in the figure, and the note up in the corner
shows us that each square has (1 inch x 1 inch) = 1 square inch of area.
You ought to be able to handle it from here.
It depends on how many boxes max puts in. If max puts 2 boxes in the larger one then the box would be approximately 350 cubic inches
