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Olenka [21]
3 years ago
5

4

Mathematics
1 answer:
Alexus [3.1K]3 years ago
3 0
Angle 4 is 150 because is is corresponding to angle 2
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1. Two walls of a room or being painted each measure 16 6/2' how many square feet will be painted
DanielleElmas [232]

Answer:

3.167 ft²

12.5 inches

Step-by-step explanation:

1.)

Measure of each wall : 16 6/2 '

Number of walls = 2

Total area to be painted :

16 6/2' * 2 = (16 + 3) * 2 = 19 * 2 = 38 inches

1 feet = 12 inches

x = 38 inches

12x = 38

x = 38 / 12 = 3.167 ft²

2.)

Area of rectangular canvas = 225

Height = 18

Base, b =?

Area of rectangle = height * base

225 = 18 * b

225 / 18 = 18b / 18

12.5 = b

Base = 12.5 inches

3 0
3 years ago
7 less than fifteen15 times a number
Viktor [21]

Answer:

15x - 7 is the algebraic translation

8 0
4 years ago
OPEN ENDED QUESTION<br> What is our final step for getting x by itself?
rodikova [14]

Answer:

Do the opposite operation

Step-by-step explanation:

If there is a coefficient like 3x, you have to divide the 3 on both sides. This is because 3x is equivalent to 3*x. The opposite of multiplication is division.

5 0
3 years ago
On the planet Joop, there are 6 gespils to every 14 vreels. If farmer
zzz [600]

Answer:

51 vreels

Step-by-step explanation:

Step 1: Given data

Ratio of gespils to vreels on the planet Joop: 6:14

Step 2: Calculate the number of gespils per 120 vreels

Elentine has 120 vreels on her rew farm. If there are 6 gespils every 14 vreels, the number of gespils is:

120 vreels × (6 gespils/14 vreels) ≈ 51 vreels

3 0
3 years ago
Find Four Numbers that form a geometric progression such that the second term is less than the first by 35, and the third term i
Olegator [25]

Answer:

  • -35/3, -140/3, - 560/3, -2240/3
  • 7, -28, 112, - 448  

Step-by-step explanation:

<u>The terms are:</u>

  • a₁, a₂, a₃, a₄

<u>Given:</u>

  • a₁ = a₂ + 35
  • a₃ = a₄ + 560

<u>Use the nth term formula:</u>

  • a₂ = a₁r
  • a₃ = a₁r²
  • a₄ = a₁r³

<u>Substitute:</u>

  • a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
  • a₁r² = a₁r³ + 560  ⇒ a₁(1 - r)r² = 560

<u>Divide the second equation by the first:</u>

  • r² = 560/35
  • r² = 16
  • r = √16
  • r = ± 4

<u>Use the first equation to find the first term:</u>

  • a₁( 1 ± 4) = 35
  • 1. a₁ = 35/-3 = -35/3
  • 2. a₁ = 35/5 = 7

<u>We have two sequences:</u>

r = 4

  • -35/3, -140/3, - 560/3, -2240/3

r = -4

  • 7, -28, 112, - 448  
8 0
3 years ago
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