All categories

2 years ago

Most jobs in computer disciplines require which minimum level of education?

Computers and Technology

2 answers:

nlexa [21]2 years ago

5 0

Answer:

B. Bachelor's Degree

Explanation:

Most computer and information systems managers work full time. Some work more than 40 hours per week. Typically, candidates need a bachelor's degree in computer or information science and related work experience. Many computer and information systems managers also have a graduate degree.

damaskus [11]2 years ago

5 0

Answer:

bachelor's degree

Explanation:

typically bachelor's degree in computer or information science

You might be interested in

1. The opportunity to create several equations for launching program files is called

vladimir1956 [14]

$\huge\underline\color{brown}\boxed{☕ANSWER:☕}$

$_________________________________$

1. The opportunity to create several equations for launching program files is called

a) creating a file

b) creating a folder

✒ c) creating a directory

d) creating a shortcut

2. Unless you specify otherwise most spreadsheet packages assume all cell addresses are

a) macros

b) relative cell reference

c) absolute cell reference

✒ d) mix cell references

3. Which of the following is not a type of lcon

a) program icon

✒ b) document icon 

c) folder icon

d) utility icon

$_________________________________$

$\normalsize\underline\color{yellow}\boxed{TheQuestionner}$

$\large\mathbb\color{orange}{Correct \: me \: if \: im \: wrong}$

7 0

2 years ago

Assume that to_the_power_of is a function that expects two integer parameters and returns the value of the first parameter raise

Bezzdna [24]

Answer:

The statement in python is as follows:

to_the_power_of(cube_side,3)

Explanation:

As stated as the requirement of the code segment, the statement takes as parameters a variable cube_side and a constant 3.

It then returns the volume of the cube; i.e. cube raise to power 3

See full program below

def to_the_power_of(val,powe):

result = val**powe

print(result)

cube_side = float(input("Cube side: "))

to_the_power_of(cube_side,3)

4 0

3 years ago

Bakit mahalaga na marunong tayong gumamit ng makina?

jeka94

Answer:

para mabilis ang gawa

Explanation:

hope it helps

5 0

3 years ago

A ____ is a structure that allows repeated execution of a block of statements.

Leokris [45]

Answer:

loop

Explanation:

Loop is the one which is used to execute the specific statement again and again until the condition is true.

In the programming, there are 3 basic loop used.

1. for loop

Syntax:

for(initialization, condition, increment/decrement)

{

statement;

}

the above statement execute until the condition in the for loop true when it goes to false, the loop will terminate.

2. while loop

Syntax:

initialization;

while(condition)

{

statement;

increment/decrement;

}

it is work same as for loop and the increment/decrement can be write after or before the statement.

3. do while

syntax:

initialization;

{

statement;

increment/decrement;

}while(condition);

here, the statement execute first then, it check the condition is true or not.

so, if the condition is false it execute the statement one time. this is different with other loops.

3 0

3 years ago

Read 2 more answers

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago