After putting the value of y from the second equation to the first equation, the resultant equation is
.
GIven:
The equations are:

It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,

Now, put this value of y in the first equation as,

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is
.
For more details about equations, refer to the link:
brainly.com/question/2263981
Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
B, -3(-4)^2+(2)4(-4) plug into a calculator