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Anuta_ua [19.1K]
3 years ago
6

If time t increases by 1 second, by how much does the distance dchange? How is this change represented in a table? In a graph?2.

If t increases by 5 seconds, by how much does d change? How is thischange represented in a table? In a graph?3. What is the walking rate per minute? The walking rate per hour?Alana : 1 meter per secondGilberto: 2 meters per secondLeanne : 2.5 meters per second
Mathematics
1 answer:
elena55 [62]3 years ago
7 0

The relationship between the time and the distance walked is an illustration of a linear equation.

<h3>The change in distance when time increases by 1 second</h3>

From the table, we have the following equations:

  • Alana: y = x
  • Gilberto: y = 2x
  • Leanne: y = 2.5x

The above equations mean that if time t increases by 1 second,

  • Alana's distance increases by 1 meter
  • Gilberto's distance increases by 2 meters
  • Leanne's distance increases by 2.5 meters

<h3>The change in distance when time increases by 5 seconds</h3>

When time increases by 5 seconds, the rate is multiplied by 5

This means that:

  • Alana's distance increases by 5 meters
  • Gilberto's distance increases by 10 meters
  • Leanne's distance increases by 12.5 meters

<h3>The walking rate per minute</h3>

The walking rate per minute is the unit rate or slopes of the linear equations.

So, the walking rates per minute are:

  • Alana's walking rate = 60 meters per minute
  • Gilberto's walking rate = 120 meters per minute
  • Leanne's walking rate = 150 meters per minute

Read more about linear equations at:

brainly.com/question/14323743

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If you help me I'll mark you branliest and give five star rating​
Olenka [21]

Answer:

See explanation for answer, hope it helps

Step-by-step explanation:

Toss; 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Total number of heads so far; 1, 1, 1, 1, 2, 3, 4, 4, 4, 5

Relative Frequency of heads so far;

\frac{1}{1} = 1.0 = 100%

\frac{1}{2} = 0.5 = 50%

\frac{1}{3} = 0.33 = 33%

\frac{1}{4} = 0.25 = 25%

\frac{2}{5} = 0.4 = 40%

\frac{3}{6} = 0.5 = 50%

\frac{4}{7} = 0.57 = 57%

\frac{4}{8} = 0.5 = 50%

\frac{4}{9} = 0.44 = 44%

\frac{5}{10} = 0.5 = 50%

Total number of tails so far; 0 1, 2, 3, 3, 3, 3, 4, 5, 5

Relative Frequency;

\frac{0}{1} = 0 = 0%

\frac{1}{2} = 0.5 = 50%

\frac{2}{3} = 0.66 = 66%

\frac{3}{4} = 0.75 = 75%

\frac{3}{5} = 0.6 = 60%

\frac{3}{6} = 0.5 = 50%

\frac{3}{7} = 0.42 = 42%

\frac{4}{8} = 0.5 = 50%

\frac{5}{9} = 0.55 = 55%

\frac{5}{10} = 0.5 = 50%

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2 years ago
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