The graph of linear equation 2x - 3y = -12 is as shown below.
I this question, we have been given a linear equation 2x - 3y = -12
We need to graph the points.
For x = 1,
2(1) - 3y = -12
2 - 3y = -12
-3y = -14
y = 14/3
For x = 0,
2(0) - 3y = -12
y = (-12)/(-3)
y = 4
For x = -1,
2(-1) - 3y = -12
-3y = -12 + 2
y = (-10) / (-3)
y = 10/3
So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)
Now we plot these points.
The graph of linear equation 2x - 3y = -12 is as shown below.
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Answer:
1232
Step-by-step explanation:
Step 1: 8x14 to find the base
Step 2: Base times Height
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The correct next step Amy could take is to factor (x^2 - 16) on the left side of the equation to yield (x + 4)(x – 4)(x + 2) = 0.
The equation is given as:
The possible next steps are:
1. Expand the equation as follows
2. Express x^2 -16 as a difference of two squares as follows
However, the correct step in this case is to factor x^2 - 16 as a difference of two squares to give
This is so, because the question says Amy is trying to solve for variable x.
This step will ensure that she gets the possible values of x, unlike expanding the whole equation .
Hence, the correct next step is
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The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t
Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
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