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2 years ago

Plz help me their is a picture

Mathematics

1 answer:

11111nata11111 [884]2 years ago

3 0

Answer:

simple. y=x+2

Step-by-step explanation:

:) ======

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Relationship B has a greater rate than Relationship A. This graph represents Relationship A.

tester [92]

Answer:

Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75

For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6

For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7

For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8

For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

4 0

3 years ago

I am confused at how to solve this question.

MrRissso [65]

110 yards 1 mile 3600 sec
-------------- * ----------------- * -------------- = 14 miles per hour (answer)
16 sec 1760 yards 1 hr

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4 years ago

Help I need to turn this in by 12:30

11Alexandr11 [23.1K]

B- -3

If x is two according to the coordinate points, that means the equation is now -8+3y=-17

Add 8 to each side- 3y=-9

And divide -9 by 3

This gets you y=-3

5 0

3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

This table shows data from a key to a map of ohio

Serga [27]

Where is the map??????

8 0

3 years ago