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3 years ago

-9.2(x-3.75)=27.6 what is the value of x

1 answer:

8 0

-9.2 (x-3.75)=27.6

is the same as
-9.2×x-(-9.2×3.75)=27.6

clean up the left side
-9.2x-34.5=27.6

add 34.5 to both sides to get rid of it on the right side
-9.2x=27.6+34.5
-9.2x=62.1

now divide both side by -8.2 to get rid of -9.2 on the left and single out the x
x=62.1/-9.2

answer
x= -6.75

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The answer is c. because the domain is the first number of each set of points

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Lostsunrise [7]

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Step-by-step explanation:

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2 years ago

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Which of the following is a solution to the equation y = 3x - 1 ?

Korvikt [17]

One way of determining the answer is by substituting the values to the equation. It is done as follows:

A. (4,1)
y = 3x - 1
1 = 3(4) - 1 = 11 -------> not equal

B. (2,5)
y = 3x - 1
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C. (4,3)
y = 3x - 1
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8 0

3 years ago

For a certain commodity the supply equation is given by S = 2p + 5 At a price of $1, there is a demand for 19 units of the commo

slava [35]

Answer:

The demand equation is: D=-4p+23

Step-by-step explanation:

To get started, we should keep in mind that the market price (p=3) occurs when supply equals demand ,therefore when p=3

S=2(3)+5=11

Thus, when p=3 D=11 and, according to the problem when p=1 D=19.

We already know two points on the demand curve. Great!

The demand equation is linear, so it has form D=bp+c.

The variable b is the slope of the demand linear equation . It can be computed through the formula

$b=\frac{y2-y1}{x2-x1}$ . equation 1

Substituting the two points (3,11) and (1,19) on equation 1.

$b=\frac{19-11}{1-3} =\frac{8}{-2}$

b=-4

Now we can find the value of intercept of the demand equation c trough point-slope form y-y1=b(x-x1).

We can use any of the points. Let's take (3,11) and write in point-slope :

y-11=-4(x-3)

y=-4x+11+12

y=-4x+23

Rewrite the linear equation according our variables D and p

D=-4P+23

Finally we found the demand equation !

5 0

3 years ago

Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.

maxonik [38]

Answer:

$42.5\:\mathrm{m^2}$

Step-by-step explanation:

The area of a sector with measure $\theta$ in degrees is given by $r^2\pi\cdot\frac{\theta}{360}$ , where $r$ is the radius of the sector.

What we're given:

$r$ of 5
$\theta$ of $195^{\circ}$

Solving, we get:

$A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}$

*Notes:

units should be in square meters (area)
the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants

7 0

2 years ago