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TiliK225 [7]
2 years ago
7

Help for good luck and a lot of money

Mathematics
2 answers:
AVprozaik [17]2 years ago
7 0

How many years of good luck are we talking about?

It would be 12.2 lbs per package

Since 24.4/2 = 12.2

It would be 97.6 lbs. for 8 packages

122 lbs. would equal out to be 10 packages.

Alex777 [14]2 years ago
5 0
1= 12.2
8=97.6
and for the last one the answer is 10 :))
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1 box contains 23 crayons, then 69 crayons can fit in ______ boxes​
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3 boxes?

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Can sum1 help me pls.i have no idea what this is :\
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It is the 2nd choice!

Step-by-step explanation:

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Pablo took out an 80/20 mortgage to buy a house that cost $140,000. The first (80%)
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$780.50

Step-by-step explanation:

I will update this if I figure how it's solved as well.

5 0
3 years ago
There is enough information to prove that triangles tno and gcm are congruent. true false
Hatshy [7]

False,  there is not enough information provided to Prove that both the triangles are congruent.

<h3>What is the congruent triangle?</h3>

Triangles have three sides and three angles, as we discovered in pre-algebra. We also discovered that a triangle's total angle is 180 degrees.

Congruent triangles are two triangles that are the same size and shape. Two congruent triangles remain congruent even if we flip, turn, or rotate one of them.

Two triangles must have the same angles and, as a result, must be congruent if their sides are the same. If two triangles are congruent or not, we may determine this simply by looking at their sides.

These two triangles are also equivalent if we know that two sides of one triangle and the angle between them are congruent to two sides and the angle between them of another triangle.

If we know that two angles and the side between them in one triangle are congruent with two angles and the side between them in another triangle, then these two triangles are probably congruent.

When two angles and a non-included side in one triangle are congruent to the corresponding angles and side of another triangle, we are left with the final scenario that results in congruent triangles.

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5 0
1 year ago
Drag each tile to the correct box.
Anni [7]

Answer:

3x^{2}y^{2}\sqrt[4]{7xy^{3}}.

Step-by-step explanation:

Since we have to find the simplified form of the expression as below

\sqrt[4]{567x^{9}y^{11}}

we will solve the expression as below

=[567x^{9}y^{11}]^{\frac{1}{4}}

=(81\times 7)^{\frac{1}{4}}\times x^{\frac{9}{4}}\times y^{\frac{11}{4}}

=81^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{\frac{8}{4}+\frac{1}{4}}.y^{\frac{8}{4}+\frac{3}{4}}

=(3^{4})^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{2+\frac{1}{4}}.y^{2+\frac{3}{4}}

=3^{1}.7^{\frac{1}{4}}.x^{2}.x^{\frac{1}{4}}.y^{2}.y^{\frac{3}{4}}

=3.x^{2}.y^{2}.(7^{\frac{1}{4}}.x^{\frac{1}{4}}.y^{\frac{3}{4}})

=3x^{2}y^{2}.(7xy^{3})^{\frac{1}{4}}

=3x^{2}y^{2}\sqrt[4]{7xy^{3}}.

7 0
2 years ago
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