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3 years ago

Which set represents the same relation as the table below?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

1) {(0,5), (4,2), (6,9), (9,10)}

Step-by-step explanation:

Edge

san4es73 [151]3 years ago

5 0

9.10 maybe i don’t know honestly its making me answer questions so i tried

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Yall im almost done pls HELP

S_A_V [24]

Answer:

61 degrees

Step-by-step explanation:

==>Given ∆MNO,

MO = 18,

MN = 6

m<O = 17°

==>Required:

Measure of <N

==>SOLUTION:

Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c

Where,

Sine A = 17°

a = 6

Sine B = N

b = 18

Thus,

sin(17)/6 = sin(N)/18

Cross multiply

sin(17)*18 = sin(N)*6

0.2924*18 = 6*sin(N)

5.2632 = 6*sin(N)

Divide both sides by 6

5.2632/6 = sin(N)

0.8772 = sin(N)

sin(N) = 0.8772

N = sin^-1(0.8772)

N ≈ 61° (approximated)

8 0

3 years ago

In a book shop, there are 12 new books on a table. 7 of the books are fiction and the rest are non-fiction. What fraction of the

3241004551 [841]

Answer:

Hi, hows life going?

Step-by-step explanation:

8 0

4 years ago

By what number should I multiply 1 1/4 to obtain 3/4

aleksklad [387]

Multiply by 3/5 (three fifths)

4 0

3 years ago

Please help me get the right answer?!

Aleksandr-060686 [28]

The answer is A, $\frac{1}{81}$ . This is because when plugging in -2 for x, the expression will look like this: $9^{-2}$ . To make the exponent positive, you have to flip it into a fraction. Then it will be $\frac{1}{9^2}$ . Lastly, you simplify the denominator into 81.

4 0

4 years ago

Read 2 more answers

Simplify this please

Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

$\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}$ Distribute exponent

$=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}$ Simplify each exponent by multiplying

$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}$ Multiplying exponents with same base

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}$ 2 + 1/3 = 7/3

$=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}$ Fractional exponents as radical form

$=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.