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stira [4]
3 years ago
14

Please help me 45 points!

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

1. mean

2. numerical data

3. median

4. bimodal

5. central tendency

6. mode

7. data

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The triangles below are similar find the value of x
avanturin [10]
Its 12 because you do 10.5/21=x/24
7 0
3 years ago
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I'm stuck on this homework question. I forgot the formula to find the side. This is 9th grade geometry.
dexar [7]

Answer:

x = 2root(22)

see image.

Step-by-step explanation:

The triangle shown is one big triangle cut into two more smaller triangles: one medium-sized and one smaller.

ALL THREE TRIANGLES ARE SIMILAR BY AA.

Set the two smaller triangles up so you can see the corresponding sides. x is the short leg in one triangle and it is the long leg in the smallest triangle. Set up a proportion.

22/x = x/4

crossmultiply

x^2 = 22•4

x^2 = 88

square root both sides.

x = sqroot(88)

x = 2sqroot(22)

see image.

3 0
3 years ago
What is the greatest common factor of 18, 6, and 36?
Viktor [21]

Answer:

18 is the greatest common factor between those

3 0
3 years ago
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Find the area of the region bounded by the line y=3x-6 and line y=-2x+8.
Vikentia [17]

Answer:

A = 12/5 units

Step-by-step explanation:

USING ALGEBRA:

We can find the intersection point between these two lines;

y = 3x - 6

y = -2x + 8

Set these two equations equal to each other.

3x - 6 = -2x + 8

Add 2x to both sides of the equation.

5x - 6 = 8

Add 6 to both sides of the equation.

5x = 14

Divide both sides of the equation by 5.

x = 14/5  

Find the y-value where these points intersect by plugging this x-value back into either equation.

y = 3(14/5) - 6

Multiply and simplify.

y = 42/5 - 6

Multiply 6 by (5/5) to get common denominators.

y = 42/5 - 30/5  

Subtract and simplify.

y = 12/5

These two lines intersect at the point 12/5. This is the height of the triangle formed by these two lines and the x-axis.

Now let's find the roots of these equations (where they touch the x-axis) so we can determine the base of the triangle.

Set both equations equal to 0.

(I) 0 = 3x - 6  

Add 6 both sides of the equation.

6 = 3x

Divide both sides of the equation by 3.

x = 2  

Set the second equation equal to 0.

(II) 0 = -2x + 8

Add 2x to both sides of the equation.

2x = 8

Divide both sides of the equation by 2.

x = 4

The base of the triangle is from (2,0) to (4,0), making it a length of 2 units.

The height of the triangle is 12/5 units.

Formula for the Area of a Triangle:

A = 1/2bh

Substitute 2 for b and 14/5 for h.

A = (1/2) · (2) · (12/5)

Multiply and simplify.

A = 12/5

The area of the region bounded by the lines y = 3x - 6 and y = -2x + 8 between the x-axis is 12/5 units.

3 0
3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0
4 years ago
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