The answer would be C since the formula for volume is lwh or bh. With this info, you know that the bases are congruent which means they are the same, as well with the height. So you just multiply the height by the base and they should be the same.
Answer:
6283 in³
Step-by-step explanation:
The largest sphere that can fit into the cardboard box must have its diameter, d equal to the length, L of the cardboard box.
Since the cardboard box is in the shape of a cube, its volume V = L³
So, L = ∛V
Since V = 12000 in³,
L = ∛(12000 in³)
L= 22.89 in
So, the volume of the sphere, V' = 4πr³/3 where r = radius of cube = L/2
So, V = 4π(L/2)³/3
= 4πL³/8 × 3
= πL³/2 × 3
= πL³/6
= πV/6
= π12000/6
= 2000π
= 6283.19 in³
≅ 6283.2 in³
= 6283 in³ to the nearest whole cubic inch
Answer:
28.875 or 28 7/8
Step-by-step explanation:
pls mark brainliest!
steps:
(23+1/2) + (15+1/8) - (9+3/4) then solve
46+1 over 2 + 120+1 over 8 - 36+3 over 4
solve
47/2 + 121/8 - 39/4
solve
188+121-78 over 8 = 231/8
convert 231/8= 28 7/8
X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub
x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
x = 9 (+-) sqrt 81 + 24)/2
x = 9 (+-) sqrt 105) / 2
x = 9/2 + 1/2 sqrt 105 or x = 9/2 - 1/2 sqrt 105
Answer:
Translations
y = f (x) + k up k units
y = f (x) - k down k units
y = f (x + h) left h units
y = f (x - h) right h units
Stretches/Shrinks
y = m·f (x) stretch vertically by a factor of m
y = ·f (x) shrink vertically by a factor of m (stretch by
y = f (x) stretch horizonally by a factor of n
y = f (nx) shrink horizontally by a factor of n (stretch by )
Reflections
y = - f (x) reflect over x-axis (over line y = 0)
y = f (- x) reflect over y-axis (over line x = 0)
x = f (y) reflect over line y = x
Hope this helps
Step-by-step explanation:
