Question

Need help finding n forgot how to do this

Answer 1

Answer:

$n = 3\sqrt{2}$

There are two best ways to solve this.

using cosine method:

$cos(n) = \frac{adjacent}{hypotenuse}$

$cos(60) = \frac{adjacent}{6\sqrt{2} }$

$adjacent,n = cos(60) * 6\sqrt{2}$

$n = 3\sqrt{2}$

using sine method:

$sin(n) = \frac{opposite}{hypotenuse}$

$sin(30)= \frac{n}{6\sqrt{2} }$

$n = sin(30) * 6\sqrt{2}$

$n = 3\sqrt{2}$

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

Answer 2

Answer:

n = 3√2

Step-by-step explanation:

A 30-60-90 triangle is a special type of triangle as the measures of the sides are x, x√3, and 2x

i.e. the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg.

We have been given the length of the hypotenuse, so we can find the value of x:

⇒  2x = 6√2

⇒  x = 3√2

We want to find the length of the shorter leg:

⇒  x = n

⇒ 3√2 = n