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DIA [1.3K]
2 years ago
8

Need help finding n forgot how to do this

Mathematics
2 answers:
andreyandreev [35.5K]2 years ago
5 0

Answer:

n  =                                    3\sqrt{2}

There are two best ways to solve this.

using cosine method:

cos(n) =  \frac{adjacent}{hypotenuse}

cos(60) = \frac{adjacent}{6\sqrt{2} }

adjacent,n = cos(60) * 6\sqrt{2}

n  =                                    3\sqrt{2}

using sine method:

sin(n) = \frac{opposite}{hypotenuse}

sin(30)=  \frac{n}{6\sqrt{2} }

n  = sin(30) * 6\sqrt{2}

n = 3\sqrt{2}

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

skad [1K]2 years ago
4 0

Answer:

n = 3√2

Step-by-step explanation:

A 30-60-90 triangle is a special type of triangle as the measures of the sides are x, x√3, and 2x

i.e. the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg.

We have been given the length of the hypotenuse, so we can find the value of x:

⇒  2x = 6√2

⇒  x = 3√2

We want to find the length of the shorter leg:

⇒  x = n

⇒ 3√2 = n

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