Answer:
113
Step-by-step explanation:
This question is incomplete, the complete question is;
For what value of a is the volume of the tetrahedron formed by the coordinate planes and the plane (x/a) + (y/10) + (z/6) = 1 equal to 10?
Answer: the value of a is 1
Step-by-step explanation:
Given that;
Volume of tetrahedron bounded by plane (x/a) + (y/10) + (z/6) = 1
and coordinate plane is; V = 1/6|abc|
(x/a) + (y/10) + (z/6) = 1
volume = 10
so
10 = 1/6 | a × 10 × 6 |
60 = a × 10 × 6
60 = 60a
a = 60 / 60
a = 1
Therefore the value of a is 1
Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.
And the expressions for each arc in the diagram also given as:
Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.
Hence, we will get the system of equations as following:
Arc QR = Arc LN
2x - y = 11 ...(1)
Arc OP = Arc VW
5x + y = 10 ...(2)
We need to find the value of x. So, we can add the equations to eliminate y so that we can solve the equations for x. Therefore,
2x+5x = 11 + 10
7x = 21
Divide each sides by 7.
So, x= 3
<h3>
Answer:</h3>
- y = -(x -3)² +3 . . . . (agrees with your answer)
- see the attachment for a graph
<h3>
Step-by-step explanation:</h3>
Factoring the leading -1 from the first two terms, we have ...
... y = -(x² -6x) -6
Adding 9 inside parentheses to complete the square, then adding the opposite amount outside parentheses, we have ...
... y = -(x² -6x +9) -6 +9
... y = -(x -3)² +3