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prohojiy [21]
2 years ago
13

Selecting the Tiled windows arrangement option places the windows in a(n) _______ pattern on the screen.

Computers and Technology
1 answer:
Archy [21]2 years ago
3 0

Answer:

Selecting the Tiled windows arrangement option places the windows in a(n) Grid pattern on the screen.

Explanation:

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What types of messages flow across an SDN controller’s northbound and southbound APIs? Who is the recipient of these messages se
Marta_Voda [28]

Answer and Explanation:

Messages flow across an SDN controller's:  

Northbound APIs:  

• Messages which help in read/write state of the network and developing flow tables within the  

state management layer.  

• Notifications for the state-change events.  

• The interaction between the controller and network control applications is done through the  

northbound interface.  

• Network control applications send messages to the controller.  

Southbound APIs:  

• Messages which help for the up-to-date view of the network's state like message for the  

attached link has gone up or down, new devices are joined the network, or indications of the  

device is up or down.  

• Controller's southbound interface is the communication among the controller and the controlled  

devices. Controlled devices are the recipients of the messages sent form the controller.  

3 0
3 years ago
Hard disk is a sequential data access medium. true or false?​
Crazy boy [7]

My answer is TRUE

Explanation:

Hope it help!!

3 0
3 years ago
To work with a different document than the one currently displayed, you would select the _____ option.
kow [346]
You would select the open button. You would have to “open” the new document.

I hope this helped!
5 0
3 years ago
Write a program that accepts three decimal numbers as input and outputs their sum​
Alex73 [517]

Answer:

sum = 0.0

for i in range(0,3):

   sum += float(input("Enter a decimal number to sum: "))

print ("Sum: ", sum)

*** Sample Input ***

Enter a decimal number to sum: 1.1

Enter a decimal number to sum: 2.2

Enter a decimal number to sum: 3.3

*** Sample Output ***

Sum:  6.6

Explanation:

For this problem, a method was devised in python to create the sum of three individual decimal numbers.

The first line of code, <em>sum = 0.0</em>, initializes a variable to the float type in which we will store the value of our sum.  Note, it is initialized to 0.0 to start from a value of 0 and be considered a float.

The second line of code, <em>for i in range(0,3):</em>  is the creation of a for loop control structure.  This will allow us to repeat a process 3 amount of times using the iterator i, from value 0 to 3 in this case.  Note, 0 is inclusive and 3 is exclusive in the python range.  This means the for loop will iterate with, i=0, i=1, and i=2.

The third line of code, <em>sum += float(input("Enter a decimal number to sum: "))</em>  is simply asking the user for a number, taking that input and converting it from a string into a float, and then summing the value with the previous value of sum and saving that into sum.

The fourth line of code, <em>print ("Sum: ", sum)</em> is simply displaying the final value that was calculated by adding the three user inputs together which were stored into the variable <em>sum</em>.

Cheers.

4 0
3 years ago
Read 2 more answers
If a stop-and-wait protocol is used, what is the fraction of time, in seconds, that the sender is busy sending bits into the cha
olganol [36]

Answer:

This question is incomplete, here is the complete question;

If a stop-and-wait protocol is used, what is the fraction of time, in seconds, that the sender is busy sending bits into the channel (the utilization), given that the round-trip-time (RTT) for a router is 20ms when sending 2000 Byte packets ( a byte is 8 bits) at 500Mega bits per second (Mbps)? Answer to the nearest tenth of a microsecond. Recall that the formula for utilization U is L/R / (L/R + RTT). Be careful of your units. Provide the answer in microseconds with one decimal place. Do not label your answer with the units, just provide the number .

Explanation:

The Answer to the question is given with proper step by step solution.

Given that : the round-trip-time (RTT in abbreviation) = 20ms = 0.02 micro seconds

L = 2000

Byte = 2000*8

bits = 16000 bits

R = 500Mbps = 500*106 bps

Now,calculate L/R = 16000 / 500*106

= 32 / 106

= 32 micro seconds

The Utilization (U) = fraction when the time sender is busy sending

= (L/R) / (L/R + RTT)

= (32) / (32 + 0.02)

= 32 / 32.02

= 0.99937539 seconds

= 999375.39 micro seconds

= 999375.4 (nearest tenth)

5 0
3 years ago
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