Given:
The equation is
To find:
The value of b.
Solution:
We have,
Subtracting both sides by 
, we get
Therefore, the value of b is 
.
K(cannot equal (the = sign with the line through it) -2
k(=/)-2
9514 1404 393
Answer:
yes
Step-by-step explanation:
10 1/2 + 8×(1/6) = (10 3/6) + (1 2/6) = 11 5/6 < 12
The weight with the added screws is still below 12 ounces.
Here we are dealing with combinations without repetitions.
Let's write the form of a name.
For names starting with W:
W _ _ _
For names starting with K:
K _ _ _
We are allowed to use only lettrs from F to X. That's total of 19 letters. We are not allowed to repeat letters so for each letter we can choose from one less available letters.
Let's start with names begining with W. We will write how man possible letters we can choose from.
W 18 17 <span>16
</span>At second possition we can choose from 18 letters because we must not repeat letters and W is placed in front of X in alphabet.
At third position we can choose from 17 letters becasue we already chose two of 19 possible letters.
At fourth position we can choose from 16 letters becasue we already chose three of 19 possible letters.
To calculate total number of possible names we need to multiply these numbers:
1 * 18 * 17 * 16 = 4896
Same calculation can be done for names starting with K. We would get same number as solution.
Total number of possible names starting with W or K is 4896 + 4896 = 9792
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
