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3 years ago

Solve 5x − 6y = −38 3x + 4y = 0

Mathematics

1 answer:

Gnesinka [82]3 years ago

5 0

Is that one or two questions?

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Y5 ÷ y0 = y4 <br> Is this correct?

jekas [21]

y^0 = 1

Thus :

y^5 ÷ 1 = y^5

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3 years ago

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The price of all rail season tickets increased by 6%. After the increase, the price of a rail season ticket from Sheffield to Le

valentina_108 [34]

Answer:

£2720

Step-by-step explanation:

106%=2883.20

100%=x

106x=288320

divide both by 106 it gives 2720

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2 years ago

Which set of numbers are equivalent?

Karolina [17]

Answer:

10% = (10÷100=1÷10)=2÷20=.10

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3 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

((Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Lina20 [59]

Answer:

Step-by-step explanation:

A series is said to be convergent if |r| < 1. Where r is the common ratio of the series.

If |r| ≥ 1 then the geometric series diverges.

12/5 + 48/25 + 192/125 + ....

r = 192/125 ÷ 48/25 = 4/5

r = 48/25 ÷ 12/5 = 4/5

In the series, r is less than 1. So the series is convergent.

5 0

3 years ago