The answer is 6.3
-12.6/-2=6.3
Answer:
20 dimes and 2 quarters
Step-by-step explanation:
x = number of dimes
y = number of quarters
minimum is greater than or equal to ≥
x+y ≥16
no more than is less than or equal to ≤ ,
value of dime is $ 0.10
value of quarter is $0.25 so
0.10x + 0.25y ≤ 3.00
Rewrite inequalities in terms of y:
y ≥16 - x
(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→
y≤12 - 0.4x
Graph system: see file
First combine like terms on each side so
8x = -7x
then move -7x
so x=0
Answer:
i think its c im not sure so it might be wrong im so sorry if its wrong
Step-by-step explanation:
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
