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2 years ago

PLEASE HELP ME I WILL GIVE BRAINLEST

Mathematics

1 answer:

Gala2k [10]2 years ago

6 0

What is this it’s so hard

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Can someone help out ??

kupik [55]

Answer:

120 cubes

Step-by-step explanation:

Find the volume of the prism and then divide it by the volume of one cube (which is 1/27 cm):

V = length*width*height = (5/3 cm)(4/3 cm)(2 cm) = 40/9 cm³.

Dividing this result by 1/27 yields

40 27 40*3

------ * ------ = -------------- = 120

9 1 1

120 cubes (answer)

7 0

3 years ago

1. What is the value of x?

sergij07 [2.7K]

Answer:

d and ef

Step-by-step explanation:

efwfnhew'foehfnwekf;esf

7 0

3 years ago

when you divide a fraction less than 1 by a whole number greater than 1, is the quotient less than, greater than, or equal to th

ratelena [41]

Answer:

less than

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please show work . . .

Alenkasestr [34]

Answer:

19.64

the permieter is 5 so 5/2=2.5 2.5x2.5=6.25 6.25x3.14=19.64

8 0

3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

$n = 345$

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0

3 years ago