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3 years ago

3/5 of 15 acres equals how many acres

Mathematics

2 answers:

elena55 [62]3 years ago

7 0

3/5 =15
Multiply 5 and 3 = 15
3 times 3 = 9
9 is the answer

kifflom [539]3 years ago

4 0

The answer is 5 acres

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Find the original price of a pair of shoes if the sale price is $22.00 after a 50% discount

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3 years ago

Y=3x+4 y=36x+7 determine whether the graph of each pair of equations are parallel, pendicularbor neither

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Parallel is the answer

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3 years ago

Find the exact value by using a half-angle identity.<br><br> tan seven pi divided by eight

murzikaleks [220]

9514 1404 393

Answer:

1 -√2

Step-by-step explanation:

$\tan(x/2)=\dfrac{1-\cos(x)}{\sin(x)}\\\\\tan\left(\dfrac{1}{2}\cdot\dfrac{7\pi}{4}\right)=\dfrac{1-\cos\dfrac{7\pi}{4}}{\sin\dfrac{7\pi}{4}}=\dfrac{1-\dfrac{1}{\sqrt{2}}}{-\dfrac{1}{\sqrt{2}}}=\boxed{1-\sqrt{2}}$

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2 years ago

Find the number of ways to distribute six different toys to three different children such that each child gets at least one toy.

Lisa [10]

Answer:

Step-by-step explanation:

Given that there are six different toys and they are to be distributed to three different children.

The restraint here is each child gets atleast one toy.

Let us consider the situation as this.

Since each child has to get atleast one toy no of ways to distribute

any 3 toys to the three children each. This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways

So 3 toys to each one in 6x5x4 =120 ways

Now remaining 3 toys can be given to any child.

Hence remaining 3 toys can be distributed in 3x3x3 =27 ways

Total no of ways

= 120(27)

= 3240

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2 years ago

The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected

mr Goodwill [35]

We have that if we assume standard exponential growth, the equation of the population will be: $7000*e^{kt}$ if we start counting from the moment that the population was 7000. We are given that 7000* $e^{5k}$ =12000, namely that P(5)=12000 and we need to find $7000e^{(5+5)k}=7000e^{10k}$ . Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000 $\frac{12000^2}{7000^2}$ = 20571 people.

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3 years ago