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mylen [45]
2 years ago
15

Find the Least Common Multiple (L.C.M) and Highest Common Factor (H.C.F) of 20 and 30.​

Mathematics
1 answer:
Archy [21]2 years ago
8 0

Answer:

LCM: 60

HCF: 10

Step-by-step explanation:

Listing Multiples

LCM:

Multiples of 20:

20, 40, 60, 80, 100

Multiples of 30:

30, 60, 90, 120

Therefore,

LCM(20, 30) = 60

----------------------------------------

Factorization

HCF:

The factors of 20 are: 1, 2, 4, 5, 10, 20

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

Then the greatest common factor is 10

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Write y = 2x + 8 in standard form.​
Setler [38]

Answer:

<u>2x - y = -8</u>

:)

8 0
2 years ago
Joel gave one fourth of his 236 postage stamps to his sister
Lorico [155]

Since one fourth is the same as 1/4 or one quarter we can do 236 / 4 = 1 quarter:

236/4 = 59 so his sister gets 59 postage stamps. Then if we do 236 - 59 we get 177 thats how many Joel has left.

4 0
3 years ago
PLZ HELPPP&lt;br /&gt;
Alexeev081 [22]
V=vanila
c=chocolate

4v+1c=45
v+c=27

mulitply 2nd equation by -1 and add to top one

-v-c=-27
<u>4v+1c=45 +</u>
<u />3v+0c=18

3v=18
divide by 3
v=6

sub back
v+c=27
6+c=27
c=21

21 choc and 6 van





A.
v+c=27
4v+1c=45
v=number of vanila wafers bought
c=number of chocolate wafers bought

B. 21 chocolate and 7
I got the answer with math because math is fun and tada
6 0
3 years ago
Show work and explain how too find the answer please I’m not fully understand the question
yulyashka [42]

Answer:

She would have 24 single shoes. This is because she has 12 pairs and there are 2 of something in each pair. Therefore, Danielle would have 24 single shoes. (12*2=24) Hope this helped!!

8 0
3 years ago
Find the volume, V, of the solid obtained by rotating the bounded region in the first quadrant enclosed by the graphs of
Delicious77 [7]

Answer:

\frac7{15}\pi

Step-by-step explanation:

First of all, let's draw the two curves. First one (red) is a classic parabola, second (blue) is a similar curve with a tigher form. Imagine is made with paint so it's not high quality. The intersection between the two curves are easily found by solving a system of equations and are (0;0) and (1;1). At this point, the volume comes from the rotation of the shaded area, and can be obtained as difference from the rotation of the blue curve minus the red curve.

Remembering that the volume of the solid of revolution bound between y=0; y=f(x); x=a; x=b is given by \pi \int_a^b [f(x)]^2dx, in our case the volume is given by the expression

\pi [\int_0^1 (\sqrt[4]{x})^2-(x^2)^2 dx] = \pi[\int_0^1 \sqrt{x}-x^4 dx]  = \pi[\frac23x^\frac32 -\frac15 x^5 ] _0^1 = \pi (\frac23 -\frac15) = \frac7{15}\pi

4 0
2 years ago
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