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m_a_m_a [10]
2 years ago
14

In going from a texas summer room temperature (35. 0°c) to 10°c above room temperature, the rate of a reaction quadruples (incre

ases by a factor of 4). Calculate the activation energy for the reaction.
SAT
1 answer:
Elza [17]2 years ago
3 0

Based on the information given, it has been computed that the activation energy will be 105.8Kj.

<h3>How to calculate activition energy</h3>

From the information given,

T1 = 25 + 273 = 298K

T2 = 35 + 273 = 308J

R = 8.314J/mol

K2/K1 = 4

Therefore,

log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]

= (0.602 × 2.303 × 8.314 × 298 × 308) / 10

= 105.8KJ

Therefore, the activation energy is 105.8KJ.

Learn more about activation energy on:

brainly.com/question/1380484

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marusya05 [52]

The probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade is: D. 0.80.

<h3>How to calculate the probability?</h3>

In this exercise, you're required to determine the probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade. Thus, we would apply Bayes's theorem.

  • Let S represent studied for.
  • Let B represent a score of B or higher grade

Therefore, we need to find P(S|B):

S|B = \frac{B|S \times S}{B|S \times S\; +\; B|S' \times S'} \\\\S|B = \frac{0.55 \times 0.6}{0.55 \times 0.6 \;+ \;0.2 \times 0.4}\\\\S|B =\frac{0.33}{0.33 + 0.08} \\\\S|B =\frac{0.33}{0.41}

S|B = 0.80.

Read more on probability here: brainly.com/question/25870256

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<u>Complete Question:</u>

At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance they will get a B or higher on the tests. If they do not study, there is a 20% chance that they will get a B or higher on the tests. The professor knows from prior surveys that 60% of students study for the tests. The probabilities are displayed in the tree diagram.

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