Question

In going from a texas summer room temperature (35. 0°c) to 10°c above room temperature, the rate of a reaction quadruples (increases by a factor of 4). Calculate the activation energy for the reaction.

Answer 1

Based on the information given, it has been computed that the activation energy will be 105.8Kj.

How to calculate activition energy

From the information given,

T1 = 25 + 273 = 298K

T2 = 35 + 273 = 308J

R = 8.314J/mol

K2/K1 = 4

Therefore,

log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]

= (0.602 × 2.303 × 8.314 × 298 × 308) / 10

= 105.8KJ

Therefore, the activation energy is 105.8KJ.

Learn more about activation energy on:

brainly.com/question/1380484