Answer:
Step-by-step explanation:
Since A = 50 degrees, c = 10 ,and since it is a right Triangle, then C = 90 degrees and so B = 180 - (90 +50)......... sum of angles of a triangle
B = 180 - 140
B = 40 degrees
Using sine rule : a/sin A = b / sin B = c / sin C
To calculate a, then we use a/ sin A = c / sin C , since we know c and C
i.e a/ sin 50 = 10 / sin 90
recall that sin 90 = 1
then we have a / sin 50 = 10 / 1
cross multiply
a = 10 x sin 50
a = 10 x 0.76604
a = 7.6604
We will calculate b following the same procedure
b/ sin B = c / sin C
b/ sin 40 = 10/ sin 90
b/ sin 40 = 10/ 1
b = 10 x sin 40
b = 10 x 0.64279
b = 6.4279
Therefore a ≈7.6604 , b ≈ 6.4279
Answer:
All those canbe expressed in the form of p/q, where q≠0 are rational
clearly A is rational
now 0.62 =62/100=31/50----its also rational
and 0.6 =6/10=3/5--- it's also rational
0.6π =(3/5)π, 3/5 is rational but π is irrational so overall it's irrational!
A,B&C are rational!
✌️:)
Answer:
32 degrees
Step-by-step explanation: So they tell you BE is congruent to BC so triangle BCE is isosceles. We know that angle C is 35 degrees and the triangle is isosceles so angle E is 35 degrees too. Now we do 180-(35+35) and that equals 110 so angle B is 110. And we know that angle EBC and FBA are supplementary angles so 180-110 is 70 degrees so angle FBA is 70 degrees and you can do the same thing with angle DFB and AFB so 180-102 degrees is 78 degrees and to find angle a you just do 180-(70+78) and that equals 32 degrees so angle A is 32 degrees. :)
Answer:
simple even tho im in 6th grade it would be over $100
Answer:
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
Step-by-step explanation:
The null and alternative hypotheses are stated as
H0: u ≥ 1750 i.e the mean is less and equal to 1750
against the claim
Ha: u > 1750 ( one tailed test) the mean is greater than 1750
Sample mean = x`= 1754
Population mean = u = 1750
Population deviation= σ = 65 pounds
Sample size= n = 100
Applying the Z test
z= x`- u / σ/ √n
z= 1754- 1750 / 65/ √100
z= 4/6.5
z= 0.6154
The significance level alpha = 0.1
The z - value at 0.1 for one tailed test is ± 1.28
The critical value is z > z∝.
so
0.6154 is < 1.28
We accept the null hypothesis that the breaking strength mean is less and equal to 1750 pounds and has not increased.
