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devlian [24]
2 years ago
11

How to connect two monitors for one desktop

Computers and Technology
2 answers:
Arte-miy333 [17]2 years ago
6 0
you get a cord that connects the 2 called a HDMI cord
Tems11 [23]2 years ago
5 0

Answer:

two HDMI cords, this will help you your monitors

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A. Ribbon just took the test
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3 years ago
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Below you will find the requirements to identify the Account Diversity Grade of a user. Read the requirements carefully and iden
igomit [66]

The technique I used to test the requirement is equivalence partitioning.

<h3>Equivalence Partitioning-</h3>

Generic test data is considered where all the test data satisfies the conditions provided in the problem. Such that,

- ADGrade A --> TA=25 LC=5

- ADGrade B --> TA=20, LC=3

- ADGrade C --> TA=8 LC=2

- ADGrade D --> TA=2, LC=1

- ADGrade null (n/a)—> TA=0, LC=0

Where:

  • TA represents totalAccounts,
  • LC represents loanTypeCount,
  • ADGrade represents accountDiversityGrade

If we are to combine the test data collected above, we would obtain the entire set of test data.

With this in mind, the minimum number of users that are required for testing the requirement is 5.

Read more about requirement testing here:

brainly.com/question/16147055

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8 0
1 year ago
A smart phone is always a _____.<br> client<br> server<br> network<br> process
kogti [31]
A smart phone should always be a client due to the fact that it gathers information from a server.
3 0
3 years ago
Compare GBN, SR, and TCP (no delayed ACK). Assume that the timeout values for all three protocols are sufficiently long such tha
kvv77 [185]

Answer and Explanation:

a)

For Go-Back-N:

  Host A sent total number of segments is 9.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2,3,4 and 5 because 2nd segment was lost.

Host B sent the number of ACKs are 8.Host B sent ACKs 1 by four times because 2nd segment was lost and sent 4ACKs with sequence numbers 2,3,4 and 5

selective repeat:

 Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence numbers 1,3,4,5 and re-sent ACK2 with sequence number 2 because 2nd segment was lost.

TCP :

Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence number 2 and There is one ACK with sequence number 6.TCP always send an ACK with expected sequence number

b) If the timeout values for all three protocol are much longer than 5*RTT,then TCP protocol successfully delivers all five data segments in shortest time interval.

 

4 0
4 years ago
Write 3 things that can't be done without technology.
bulgar [2K]

Answer:

Hacking Online Orders Math

Explanation:

4 0
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