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Julli [10]
3 years ago
6

The table shows the pricing for four different brands of cat food.

Physics
1 answer:
Levart [38]3 years ago
4 0

Answer:

D

Explanation:

trust me bro

You might be interested in
__________ is the correct method of recording numerical information from an experiment.
choli [55]

Answer:

The quantitative method

Explanation:

<em>Quantitative method is the use of numbers, graphs, logic, tables, charts, stadistics, etc.</em> This kind of method is objective, can be replicated and repeated, and it collects numeric data.

I hope you find this information useful and interesting! Good luck!

8 0
3 years ago
You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti
vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

The change in entropy is:

dS = dQ/T

Since the room temperature is constant (isothermal):

ΔS = ΔQ/T

Plug in values (remember to use absolute temperature):

ΔS = (68,000 J) / (293 K)

ΔS = 232 J/K

5 0
3 years ago
Find the force in newtons that does 0.0284 kilojoules of work in moving a book a distance of 4.00 meters
gulaghasi [49]

Work = (force) x (distance

28.4 joules = (force) x (4 meters)

Divide each side by (4 meters) :

Force = (28.4 joules) / (4 meters)

Force = 7.1 Newtons

5 0
4 years ago
A 755 N diver drops from a board 10.0 m above the water's surface. Find
MrRa [10]

Answer:

F = 755 N and h = 10.0 m and a = 9.8 m/s 2 and m=? and v = ?

5 0
3 years ago
I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52
Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

u_x = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

a_y = Acceleration in y axis = 9.81\ \text{m/s}^2

u_y = Initial velocity in y axis = 0

y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}

v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction u_x=v_x=1.52\ \text{m/s}

Resultant velocity is given by

v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}

The fish is moving at a velocity of 28.1 m/s when it hits the water.

6 0
3 years ago
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