You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti
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Answer:
The additional charge that will flow from the battery onto the positive plate is 0.924 nC
Explanation:
Given;
Area of the capacitor, A = 15.0 cm² = 15 x 10⁻⁴ m²
Separation distance, d = 3.00 mm = 3 x 10⁻³ m²
voltage of the capacitor, V = 58.0 V
dielectric constant, k = 4.60
Initial Capacitance of the capacitor before the addition of dielectric material:
Initial charge across the parallel plates:
Q₁ = CV
Q = 4.425 x 10⁻¹² x 58 = 2.567 x 10⁻¹⁰ C
Capacitance of the capacitor after the addition of dielectric material:
Cequ. = Ck
Cequ. = 4.425 x 10⁻¹²F x 4.6 = 20.355 x 10⁻¹² F
Final charge across the parallel plates:
Q₂ = Cequ. x V
Q₂ = 20.355 x 10⁻¹² x 58 = 11.806 x 10⁻¹⁰ C
Additional charge = Q₂ - Q₁
= 11.806 x 10⁻¹⁰ C - 2.567 x 10⁻¹⁰ C
= 9.239 x 10⁻¹⁰ C
= 0.924 nC
Therefore, the additional charge that will flow from the battery onto the positive plate is 0.924 nC
Answer:
The distance traveled by the tuning fork is 9.37 m
Explanation:
Given;
source frequency, = 683 Hz
observed frequency, = 657 Hz
The speed at which the tuning fork fell is calculated by applying Doppler effect formula;
where;
is speed of sound in air = 343 m/s
is the speed of the falling tuning fork
The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;
where;
is the initial speed of the tuning fork = 0
g is acceleration due to gravity = 9.80 m/s²
Therefore, the distance traveled by the tuning fork is 9.37 m