Answer: 16N
Explanation:
According to coulombs law which states that the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically,
F = kq1q2/r²
If two charges that are separated by one meter exert 1-N forces on each other, the equation will become
1 = kq1q2/1²
kq1q2 = 1 ... (1)
If the charges are pushed together so the separation is 25 centimeters, the force between them becomes,
F = kq1q2/0.25² (25cm converted to meters)
0.0625F = kq1q2 ... (2)
Dividing equation 1 by 2 to determine the force F on each charges, it becomes;
1/0.0625F = kq1q2/kq1q2
1/0.0625F = 1
0.0625F = 1
F = 1/0.0625
F= 16N
Answer:
3 x 10⁻⁴m
Explanation:
Given parameters:
Speed of light = 300000km/s
Frequency = 1000gigahz = 1000 x 10⁹Hz
Unknown:
Wavelength = ?
Solution:
To solve this problem, we use the expression below:
V = F ∧
V is the speed
F is the frequency
∧ is the wavelength
300000 = 1000 x 10⁹ x ∧
Wavelength = 3 x 10⁻⁷km = 3 x 10⁻⁴m
Answer:
26.5 m/s
Explanation:
The tension in the string provides the centripetal force that keeps the toy in circular motion. So we can write:

where:
T is the tension in the spring
m = 0.50 kg is the mass of the toy
r = 1.0 m is the radius of the circle (the length of the string)
v is the speed of the toy
The maximum tension in the string is
T = 350 N
If we substitute this value into the equation, we find the maximum speed that the mass can have before the string breaks:

At first I thought it was the force of friction acting opposite the direction of motion, but I would say it is not a force. I'm not sure how you can experience a change in acceleration without there being a force