Question

) A 1000-nF capacitor with circular parallel plates with a radius of 1cm is accumulating charge at the rate of 52 mC/s at some point in time. What will be the induced magnetic field strength if you are positioned 20 cm radially outward from the center of the plates

Answer 1

Answer:

$B=5.2*10^-^8T$

Explanation:

From the question we are told that

Capacitor $c=1000nf$

Radius $r=1cm =>0.001m$

Charge rate $Q/t=52mC/s$

Distance $d=20cm =0.2m$

Generally the rate of charge I is mathematically given as

$I=\frac{dQ}{dt}$

$I=52Cm/s$

$I=52*10^-^3C$

Generally the the magnetic field intensity at distance d is mathematically given as

$B=\frac{\mu I}{2\pi d}$

$B=\frac{(4 * \pi *10^-^7)(52*10^-^3C)}{2\pi (0.2)}$

$B=5.2*10^-^8T$