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never [62]
3 years ago
10

) A 1000-nF capacitor with circular parallel plates with a radius of 1cm is accumulating charge at the rate of 52 mC/s at some p

oint in time. What will be the induced magnetic field strength if you are positioned 20 cm radially outward from the center of the plates
Physics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

B=5.2*10^-^8T

Explanation:

From the question we are told that

Capacitor c=1000nf

Radius r=1cm =>0.001m

Charge rate Q/t=52mC/s

Distance d=20cm =0.2m

Generally the rate of charge I is mathematically given as

I=\frac{dQ}{dt}

I=52Cm/s

I=52*10^-^3C

Generally the the magnetic field intensity at distance d is mathematically given as

B=\frac{\mu I}{2\pi d}

B=\frac{(4 * \pi *10^-^7)(52*10^-^3C)}{2\pi (0.2)}

B=5.2*10^-^8T

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Answer:

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