Answer:
10
Step-by-step explanation:
We require to find the cube root (n = 3) pf a = 1000, that is
the root is
![\sqrt[3]{1000}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D)
= 10 ( since 10 × 10 × 10 = 1000 )
make 1 3/4 an improper fraction:
1 3/4 = 7/4
now you have 4/7 divided by 7/4
now reverse the 7/4 and multiply:
4/7 x 4/7 = 16/49
A. X is the number of years after 2000
2006-200 = 6 years.
Replace x with 6 and solve:
105(6)^2 + 680(6) + 4296 = 12,156
Answer for part a: 12,156
Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75
6 years x .75 = 4.5 years
6 + 4.5 = 10.5 years round to 10 years for estimating purposes
Answer for part b: about 10 years
Answer:
-194, -97, -48.5
Step-by-step explanation:
-3,104 ÷2 is -1,552. I divided each number by 2.
You can take 3x as a common factor from them, then it would be:
3x (5+8a) ......so, it's the equivalent form of that...
