Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
Answer:
the answer is 5
Step-by-step explanation:
f(4) = 3(4) -2
7 - 2 = 5
The answer is Eight ninetieths
Pls mark as brainliest thx
14 + {-2 + 3[1 + 3(-6-2)]}
14 + { -2 + 3[1 + 3(-8)]}
14 + { -2 + 3[1 - 24]}
14 + { -2 + 3[-23]}
14 + {-2 - 69}
14 + {-71}
14 - 71
- 57 <==
<span>It is possible to have an obtuse triangle that also contains a 35° angle.
Yes, this is true.
That's because an obtuse angle just means it's more than 90 but less than 180 degrees.
</span><span>It is possible to have a right triangle that also contains a 110° angle.
</span>No, this is false.
That's because a right triangle already has 90. That means that the two remaining angles must add up to 90 and not more or less.
<span>It is possible to have an acute triangle that also contains a 70° angle.
Yes, this is true.
An acute triangle means that all of the angles are more than 0 but less than 90.
Hope this helps :)</span>
