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Veronika [31]
3 years ago
15

Solve four tenths plus four ninths

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0
The answer is Eight ninetieths
Pls mark as brainliest thx
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The total cost to attend the university Daniel wants to attend is going to be $12,000 for the first year.
Zielflug [23.3K]

Answer:

$395.83

Step-by-step explanation:

to solve, we first need to subtract what we already have, first the scholarship, wich is a set amount being taken from the original amount

12'000 - 2'500 = 9'500

now we have the second subtracting factor, but this one isn't set in stone and defined, it is half of the amount his parents will pay, so what we can do is divide what we have by two, wich will give us 2 halves

9'500 / 2 = 4'750

now all we have to do is divide again but this time for each month that Daniel needs to save up in, in this case 12

4'750 / 12 = 395.83 (note1)

and there we have it, that is the minimum amount Daniel would save each month

note1: (3 goes on for infinity, usualy this is represented by a line above the repeating number, this is the case of a repeating decimal)

5 0
3 years ago
ALGEBRA FINAL HELP PLEASE!!! ASAP!!!
Slav-nsk [51]

Answer: I am pretty sure the answer is

g(x) = (x+3)^2 +9

Consider brainleist?

Hope this helped

:D

8 0
3 years ago
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = \frac{9}{7+9}\times (x)

                                      = \frac{9}{16}\times (x)

And the weight of zinc = \frac{7}{7+9}\times (x)

                                      = \frac{7}{16}\times (x)

If the weight of zinc = 31.5 kg

31.5 = \frac{7}{16}\times (x)

x = \frac{16\times 31.5}{7}

x = 72 kgs

Therefore, weight of copper = \frac{9}{16}\times (72)

                                               = 40.5 kgs

2). i). 2 : 3 = \frac{2}{3}

        4 : 5 = \frac{4}{5}

Now we will equalize the denominators of each fraction to compare the ratios.

\frac{2}{3}\times \frac{5}{5} = \frac{10}{15}

\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}

Since, \frac{12}{15}>\frac{10}{15}

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = \frac{11}{19}

    19 : 21 = \frac{19}{21}

By equalizing denominators of the given fractions,

\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}

And \frac{19}{21}\times \frac{19}{19}=\frac{361}{399}

Since, \frac{361}{399}>\frac{231}{399}

Therefore, 19 : 21 > 11 : 19

iii). \frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}

             =\frac{3}{2}

     \frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}

              = \frac{4}{3}

Now we equalize the denominators of the fractions,

\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}

And \frac{4}{3}\times \frac{2}{2}=\frac{8}{6}

Since \frac{9}{6}>\frac{8}{6}

Therefore, \frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4} will be the answer.

IV). 1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}

                  =\frac{6}{5}\times \frac{3}{4}

                  =\frac{18}{20}

                  =\frac{9}{10}

Similarly, \frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}

                       =\frac{4}{15}                  

By equalizing the denominators,

\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}

Similarly, \frac{4}{15}\times \frac{20}{20}=\frac{80}{300}

Since \frac{270}{300}>\frac{80}{300}

Therefore, 1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}

V). If a : b = 6 : 5

     \frac{a}{b}=\frac{6}{5}

        =\frac{6}{5}\times \frac{2}{2}

        =\frac{12}{10}

  And b : c = 10 : 9

  \frac{b}{c}=\frac{10}{9}

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

7 0
3 years ago
The marked price of a machine is $1200. How much will it cost if there is a discount of 20%? *
fredd [130]

Answer:

discount amount=20%of mp

=240

now sp=mp-discount=1200-240=960

3 0
3 years ago
Two standard 6-sided number cubes are rolled, a red one and a blue one. How many different sums are possible? ​
AlladinOne [14]

Answer:

There are 11 different sums.

Step-by-step explanation:

When you roll two dice, the smallest number you can get is 2, and the largest 12, and you can get all in between. So 12-2 is equal to 10, but we have to add another 1 because 2 counts. So the answer is 11.

8 0
3 years ago
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