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2 years ago

GUYS PLEASE HELP ME

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

6 0

Answer:

x = 54° y = 126°

Step-by-step explanation:

Interior angles of a triangle = 180°

Therefore x = 180 - 80 - 46 = 54°

y = 180 - x = 180 - 54 = 126°

exis [7]2 years ago

3 0

Answer:

X is 54 because 54+80+46=180 and y should be 34 because 80-46=34

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3 years ago

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1 year ago

Solve the inequality 16

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2 years ago

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 117.7-cm and a standard dev

Andre45 [30]

Answer:

Required probability is 0.9748

Step-by-step explanation:

given data

mean $\mu$ = 117.7-cm

standard deviation $\sigma$ = 2.2-cm

sample size n = 29

solution

we consider here random variable which represents here length of rod= x

so get here first z that is express as

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put here value with x value 118.5-cm

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7 0

3 years ago

ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

7 0

3 years ago