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Umnica [9.8K]
2 years ago
5

What is the mode of 31, 29, 33, 37, 43, 38, 33 and 40

Mathematics
1 answer:
slega [8]2 years ago
8 0

Answer:

33

Step-by-step explanation:

The answer is 33 since it is the number that is most repeated.

That is was the mode is.

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5(wx-v)=9(x+v)<br> make x the subject
Zepler [3.9K]
Expand the brackets first
5(wx-v) = 9(x + v) 
5wx - 5v = 9x + 9v

Get all x's on one side and everything on on the other side
9x - 5wx = 9v + 5v

factorise out the x
x(9-5w) = 14v

then divide by 9-5w
x = 14v/(9-5w)


3 0
3 years ago
Read 2 more answers
The sum of a whole number and twice its square is 21. Find the whole number
I am Lyosha [343]
SOLUTION:

Let whole number = x

x + 2x^2 = 21

2x^2 + x - 21 = 0

2x^2 + 7x - 6x - 21 = 0

x ( 2x + 7 ) - 3 ( 2x + 7 ) = 0

( 2x + 7 ) ( x - 3 ) = 0


2x + 7 = 0

2x = - 7

x = - 7 / 2

OR

x - 3 = 0

x = 3


ANSWER:

Therefore, as 3 is a whole number while - 7 / 2 isn't a whole number, the whole number must be 3.

Hope this helps! :)
Have a lovely day! <3
6 0
3 years ago
X+7=4 Algebraic equation
Vaselesa [24]
The answer is x=  

-3

Hope I helped!

5 0
3 years ago
Read 2 more answers
4(-2d-3)=12, someone please solve this for me asap
wlad13 [49]

4(-3 + -2d) = 12

(-3 * 4 + -2d * 4) = 12

(-12 + -8d) = 12

-12 + -8d = 12

-12 + 12 + -8d = 12 + 12

-12 + 12 = 0

0 + -8d = 12 + 12

-8d = 12 + 12

12 + 12 = 24

-8d = 24

d = -3

5 0
3 years ago
A path 2.5m wide is running outside a square field whose side is 45m. Determine the area of the path.
aliya0001 [1]

Answer:

The area of the path would be 231.25 squared meters.

Step-by-step explanation:

Consider the path as 45m (the field's area), then add 2.5m to all of the sides. You'll get 47.5m on all sides. Then you do 47.5² to get 2256.25 squared meters. After that, you'll remove the area of the squared field. To do this, do 45m². By doing this, you'll get 2025 squared meters. Lastly, to finish up the question, do 2256.25 - 2025. This would get you 31.25 squared meters, the answer.

4 0
3 years ago
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