<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span><span>Trapezoid area = [(8.2 + 5.9) /2] * 10
</span><span>Trapezoid area = (14.1 / 2) * 10
</span><span>Trapezoid area =7.05 * 10
</span><span>Trapezoid area = 70.50
</span>
Source:
http://www.1728.org/quadtrap.htm
Answer:
Step-by-step explanation:
4^x-5 = 6
<u>Apply the ln rule</u>
x^y = z
(y)*ln(x) = z
4^x-5 = 6
(x-5)*ln(4) = ln(6)
x-5 = ln(6)/ln(4)
x-5 = 1.292
x = 6.292
Therefore, the correct answer is the last option.
!!
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575
</span> For the domain we have:
<span> </span>We match zero:
-4.92t ^ 2 + 17.69t + 575 = 0
We look for the roots:
t1 = -9.16
t2 = 12.76
We are left with the positive root, so the domain is:
[0, 12.76]
For the range we have:
We derive the function:
h '(t) = - 9.84t + 17.69
We equal zero and clear t:
-9.84t + 17.69 = 0
t = 17.69 / 9.84
t = 1.80
We evaluate the time in which it reaches the maximum height in the function:
h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
h (1.80) = 590.90
Therefore, the range is given by:
[0, 590.9]
Answer:
the domain and range are:
domain: [0, 12.76] range: [0, 590.9]
Answer:
45/100 or 2.22/10
Step-by-step explanation:
43 + 47 = 90 90 ÷ 2 + 45
100 ÷ 45 = 2.22
Answer:
yes
Step-by-step explanation:
16/7 = 2.28
80/35 = 2.28
