So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
In order for a certain reaction to be spontaneous, the change in Gibb's free energy must be negative, that is:
dG < 0
We can calculate dG using:
dG = dH - dS
When we plug in the given values, we see that the sign of dG will never be negative; therefore, the reaction will not be spontaneous under any conditions.
Answer:
232 g CO2
2 C8H18 + 25 O2 --> 16 CO2 + 18 H2O
75.3 g C8H18 (1mol / 114.26g) (16 mol CO2/2 mol C8H18) (44.01 g/1 mol) = 232 g
Hope this helps!
Iodine&chlorine contain negative charge.so they are anion.When we do electrolysis those charge go to anod&become ion.
