At atmospheric pressure water boils at 100 degC.
So the water would be gas/vapor/steam.
Answer:
HNO3(aq) + OH-(aq) → NO3-(aq) + H2O(l)
Explanation:
According to Bronsted-Lowry theory, an acid is a substance that donates a proton (H+) and produces a conjugate base while a base is a molecule or ion which accepts the proton.
An example of Bronsted-Lowry acid and base is Nitric acid, HNO3 and hydroxide ion, OH- respectively as shown in the given reaction.
Thus, the nitric acid acts as an acid by donating a proton to the hydroxide ion which accepts it, thus producing nitrate ion, NO3- as a conjugate base, while OH- produces H2O as a conjugate acid.
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:
The empirical formula is CH3O2
Explanation:
From The question, number of moles of CO2= 4.89/44=0.111mol
Number of moles of H2O=3/18= 0.1667moles
Since 1mole of CO2 contains 1mole of carbon and 2 moles of O2,
Implies that there 0.111 moles of C and 0.222moles of O2
Similarly also 0.1667moles of water contains 2 moles of H2 hence = 0.333 moles of H2
Dividing by smallest number= 0.111mol
For C = 0.111/0.111= 1
For H = 0.333/ 0.111= 3
For O = 0.222/0.111= 2
Hence the empirical formula= CH3O2
