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3 years ago

This beaker contains an aqueous solution of copper II nitrate.

Chemistry

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

See the answer below

Explanation:

<em>Aqueous solution of copper II nitrate contains solute of copper II nitrate dissolved in water</em>. The equation for the reaction is as below:

$Cu(NO_3)_2 (s)$ + $H_2O (l)$ --> $Cu(NO_3)_2 (aq)$

Hence, the solute chemical is copper II nitrate while the solvent is water.

Chemical formula of copper II nitrate - $Cu(NO_3)_2$

Chemical formula of water - $H_2O$

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To calculate the molarity of acid, we use the equation given by neutralization reaction:

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$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

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$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

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