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Nutka1998 [239]
2 years ago
11

Is 1 1/4 closer to 1 or 2?​

Mathematics
2 answers:
stira [4]2 years ago
3 0

Answer:

It is closer to 1.

Step-by-step explanation:

Think about this:

1 1/4 is 1/4 closer to one.

1 1/4 is 3/4 closer to two.

maks197457 [2]2 years ago
3 0

Answer:

1

Step-by-step explanation:

1 1/4 can be represented as 1.25 as a decimal.

Any decimal that is 1.5 or is higher will round up to 2, and anything that is 1.49 or lower will round down to 1.

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Evaluate the expression for the given value of the variable(s). 5a + 5b; a = -6, b = -5
Vika [28.1K]
Your answer is A. You literally plug in the numbers for a and b to solve for the equation.

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3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

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Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

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