The value of current solubility product is calculated as below
K = (Ag+)( Cl-)
Ag+ = 0.01 M
Cl-= 1 x10^-5M
K is therefore = 1 x10^-5 x 0.01 = 1 x10 ^ -7 M
The K obtained is greater than Ksp
that is K> KSp
1x10^-7 > 1.7 x10 ^-10
will precipitation of AgCl form?
yes the precipitation of AgCl will be formed since K> KSP
Answer:
The three major types of bond are ionic, polar covalent, and covalent bonds. Ionic occurs majorly between metals and non-metals, which allows sharing of electrons to form an ionic compound. Whereas covalent bonding calls for complete transfer of electrons between atoms. Polar covalent bonds have unequaly shared electron-pair between two atoms.
Explanation:
a. Cu (Copper)-<em> ionic bonding
</em>
b. KCl (Potassium Chloride)
- <em>ionic bonding
</em>
c. Si (Silicon)
- <em>covalent bonding
</em>
d. CdTe (Cadmium Telluride)
- <em>polar covalent bonding
</em>
e. ZnTe (Zinc Telluride)- <em>polar covalent bonding
</em>
Answer:
top one is anaphase and the middle one is cytokinesis can't see enough of the bottom one to tell
Explanation:
It will be great if you searched on the internet then just questioning it on here because on here it takes a bit to get that so might as well google it
Answer:
A. 140,800 J
Explanation:
Specific heat of a material is defined as the amount of energy required to increase in 1°C 1kg of the material. <em>For wood there are required 1760J perkg per °C.</em>
The equation is:
Q = C*m*ΔT
<em>Where Q is heat in Joules,</em>
<em>C is specific heat (1760J/kg°C),</em>
<em>m is mass (2kg)</em>
<em>ΔT is change in temperature (50°C - 10°C = 40°C)</em>
Replacing:
Q = 1760J/kg°C*2kg*40°C
Q = 140800J
Right option is:
<h3>A. 140,800 J
</h3>
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