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LenaWriter [7]
3 years ago
9

Need to know how many grams of Cr2O3 can react with 50.0 grams os Si?

Chemistry
1 answer:
larisa86 [58]3 years ago
5 0
It will be great if you searched on the internet then just questioning it on here because on here it takes a bit to get that so might as well google it
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Consider the rate law below.
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C. quadruples the rate

<h3>Further explanation</h3>

Given

The rate law :

R=k[A]²

Required

The rate

Solution

There are several factors that influence reaction kinetics :  

  • 1. Concentration  
  • 2. Surface area  
  • 3. Temperature  
  • 4. Catalyst  
  • 5. Pressure  
  • 6. Stirring  

The rate is proportional to the concentration.

If the concentration increased, the reaction rate will increase

The reaction is second-order overall(The exponent is 2)

The concentration of A is doubled, the reaction rate will increase :

r = k[A]² ⇒ r= k[2A]²⇒r=4k[A]²

<em>The reaction rate will quadruple.</em>

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3 years ago
In a certain variety of plants, red flowers appear in majority of plants and blue flowers appear only in a few plants. Which sta
Jlenok [28]

Answer:

C

Explanation:

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4 years ago
Question 3 of 8
vitfil [10]

Answer:

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Explanation:

7 0
3 years ago
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A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
Romashka [77]

Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

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3 years ago
Which element am I? Give my symbol ONLY! What a robber says as he's running away! ​
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Answer:

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Explanation:

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