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2 years ago

Multiplying Polynomials Distributive property 4a^2(a^5-2a^4+a)

Mathematics

1 answer:

Nana76 [90]2 years ago

6 0

Answer:

hey this is your anwser -16e^8+20e^4

Step-by-step explanation:

hey i think the girl in your pfp look supper cute i was wondering if you would like to get to know eachother better and be friends for a little bit

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Get 20 points, Plz help me with this question, and give the right answer cause it's important

Aliun [14]

Answer:

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Step-by-step explanation:

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2 years ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

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2 years ago

Solve please. Correctly 3(1 - 2a) = -3a - 18

True [87]

Answer:

a = 7

Step-by-step explanation:

3(1 - 2a) = -3a - 18

3 - 6a = - 3a - 18

Add 18 to each side:

3 + 18 - 6a = - 3a - 18 + 18

21 - 6a = - 3a

Add 6a to each side:

21 - 6a + 6a = - 3a + 6a

21 = 3a

3a = 21

Divide each side by 3:

3a ÷ 3 = 21 ÷ 3

a = 7

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2 years ago

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3 years ago

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otez555 [7]

Answer:

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Step-by-step explanation:

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2 years ago