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BARSIC [14]
3 years ago
5

Mindy conducted a survey of the phones in 4 stores and wrote The Following observations:

Mathematics
1 answer:
balu736 [363]3 years ago
5 0
The first one is 75% i think I dont know if thats the answer though hold on and I'll get you the others

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(X^3-7x+4)+(2x+x-10)
lana66690 [7]
The answer is x^3-4x-6.
4 0
3 years ago
Determine whether the three points are collinear.<br> (0, - 10). (-3,- 13), (2,-8)
LUCKY_DIMON [66]

Answer:

<h2>YES. These points are collinear.</h2>

Step-by-step explanation:

If three points are collinear, then the slopes are the same.

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

For (0, -10) and (-3, -13):

m=\dfrac{-13-(-10)}{-3-0}=\dfrac{-13+10}{-3}=\dfrac{-3}{-3}=1

For (-3, -13) and (2, -8):

m=\dfrac{-8-(-13)}{2-(-3)}=\dfrac{-8+13}{2+3}=\dfrac{5}{5}=1

We can check the last pair (0, -10) and (2, -8):

m=\dfrac{-8-(-10)}{2-0}=\dfrac{-8+10}{2}=\dfrac{2}{2}=1

5 0
3 years ago
Find the missing side length to the nearest tenth of a millimeter.
Zarrin [17]

Answer:

A = 4.7

Step-by-step explanation:

To find the missing leg, use this formula:

a = \sqrt{c^2 - b^2}

----------------------------------------------------------------------------------------------------------------

Have a good day :)

5 0
3 years ago
The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for
4vir4ik [10]
A) g=f' is continuous, so f is also continuous. This means if we were to integrate g, the same constant of integration would apply across its entire domain. Over 0, we have g(x)=2x. This means that


f_{0


For f to be continuous, we need the limit as x\to1^- to match f(1)=3. This means we must have


\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2


Now, over x, we have g(x)=-3, so f_{x, which means f(-5)=17.


b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,


\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10


c) f is increasing when f'=g>0, and concave upward when f''=g'>0, i.e. when g is also increasing.

We have g>0 over the intervals 0 and x>4. We can additionally see that g'>0 only on 0 and x>4.


d) Inflection points occur when f''=g'=0, and at such a point, to either side the sign of the second derivative f''=g' changes. We see this happening at x=4, for which g'=0, and to the left of x=4 we have g decreasing, then increasing along the other side.


We also have g'=0 along the interval -1, but even if we were to allow an entire interval as a "site of inflection", we can see that g'>0 to either side, so concavity would not change.
5 0
3 years ago
24x=3y solve for x and y
olga2289 [7]
\ 24x=3y \\ \\ \ x=3 \ ; \ y=24
4 0
4 years ago
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