10 x 2 = 20 6 x 2 = 12
20+12=32
the perimeter is 32ft
The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.
Multiply top and bottom numbers by 10 then divide :)
Answer:
∠CAD = 44⁰
∠ACD = 44⁰
∠ACB = 136⁰
∠ABC = 22⁰
Step-by-step explanation:
To calculate m∠CAD;
Line AD = Line DC,
thus ∠CAD = ∠ACD = ¹/₂(180 - 92°) [sum of angles in a triangle.]
∠CAD = ¹/₂ x 88 = 44⁰
Also, ∠ACD = 44⁰
To calculate m∠ACB;
∠ACB = 180 - ∠ACD [Sum of angles on a straight line]
∠ACB = 180 - 44
∠ACB = 136⁰
To calculate m∠ABC;
Line CB = Line CA
Thus, ∠ABC = ∠CAB = ¹/₂(180 - ∠ACB) [sum of angles in a triangle.]
∠ABC = ¹/₂(180 - 136)
∠ABC = ¹/₂ x 44
∠ABC = 22⁰
Answer:
11x^3−2x^2+3x+11 this is the correct answer