Question

If a line has a slope of 4 and contains the point (-2, 5), what is its equation in

Answer 1

Answer: A. y - 5 = 4(x + 2)

$\rule{130}{1}$

$\rule{1}{5 } \ \ \sf point \ slope \ form : y-y_1 = m(x - x_1) \quad \ where \ (x_1 , \ y_1)\ are \ points \ \ \ \rule{1}{5}$

                                                   Given points: (-2, 5)

solving stepwise:

$\rightarrow y - 5 = 4(x - (-2))$

$\rightarrow y - 5 = 4(x +2) \bf \quad \quad This \ is \ point \ slope \ form$

$\rightarrow y - 5 = 4x + 8$

$\rightarrow y = 4x + 13 \quad \quad \quad \quad \bf This \ is \ slope \ intercept \ form$

Answer 2

Answer:

B. y-5= 4(x-2)

Step-by-step explanation:

I'm not sure how to describe it, believe me tho but if my answer is incorrect my fault then.