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guapka [62]
2 years ago
9

Y=¼ x + 2.5 y=⅕ x + 3 solve using substitution or elimination

Mathematics
2 answers:
lutik1710 [3]2 years ago
7 0

Answer:

Step-by-step explanation:

posledela2 years ago
3 0

Answer:

x=1/10

Y=5

Step-by-step explanation:

1/4x+2.5 =1/5x+ 3

x=1/10

Y=1/4×1/10+2.5

Y=5

×=1/10

Y=5

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What is the area of the trapezoid?
nalin [4]

Answer:

The answer is 36 squared centimeters

8 0
3 years ago
What is the solution to this inequality?
stira [4]

Answer:

Move all terms not containing x to the right side of the inequality. x < 9

Step-by-step explanation:

Move all terms not containing x to the right side of the inequality. x < 9

6 0
3 years ago
Write a function describing the relationship of the given variables.
Oliga [24]

Answer:

The function describing the relationship of V and t is V = 3t²

Step-by-step explanation:

* Lets explain the meaning of direct variation

- The direct variation is a mathematical relationship between two

  variables that can be expressed by an equation in which one

  variable is equal to a constant times the other

- If Y is in direct variation with x (y ∝ x), then y = kx, where k is the

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* Now lets solve the problem

# V is varies directly with the square  of t

- Change the statement above to a mathematical relation

∴ V ∝ t²

- Chang the relation to a function by using a constant k

∴ V = kt²

- To find the value of the constant of variation k substitute V and t

 by the given values

∵ t = 6 when V = 108

∵ V = kt²

∴ 108 = k(6)² ⇒ simplify the power 2

∴ 108 = 36k ⇒ divide both sides by 36 to find the value of k

∴ 3 = k

- The value of the constant of variation is 3

∴ The function describing the relationship of V and t is V = 3t²

3 0
3 years ago
ind the length of the longest side of the rectangle whose vertices are given. A(2, 1), B(5, 4), C(0, 3), D(3, 6) 2 rad2 3 rad2 r
trasher [3.6K]

Distance between A and B  

= Distance between C and D  

= sqrt((4 - 1)^2 + (5 - 2)^2)  

= sqrt(3^2 + 3^2)  

= sqrt(2 * 3^2)  

= sqrt(3^2) * sqrt(2)  

= 3sqrt(2)  

Distance between B and C  

= Distance between A and D  

= sqrt((4 - 3)^2 + (5 - 0)^2)  

= sqrt(1^2 + 5^2)  

= sqrt(26)  

Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).

Hope this helps you.

5 0
3 years ago
I have a math problem:<br> I also attached the possible values I was given. Please Help!
vekshin1

Answer:

I solved it and my answer is - 1.2

8 0
3 years ago
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