Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
a) b ≈ 100
b) m ≈ 30
Step-by-step explanation:
Answer:
h = 9 ft
Step-by-step explanation:
Assume the diagram is like the one below.
∆ABD is a right triangle.
We can use Pythagoras' Theorem to find the height h.

Answer:
The number of children's tickets sold was 27
Step-by-step explanation:
Let
x ----> the number of children's tickets sold
y ----> the number of adult's tickets sold
we know that
----> equation A
----> equation B
Solve the system by substitution
Substitute equation B in equation A

solve for x



therefore
The number of children's tickets sold was 27