2+3+4+5+y+7+8+9+10c11+12+13+14+15
Trey designed 105 games, so he designed 70 more games. The way the question is worded is weird.
2(|x−3|)−4≥10
Step 1: Add 4 to both sides.<span><span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>−4</span>+4</span>≥<span>10+4</span></span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>≥14</span>Step 2: Divide both sides by 2.<span><span><span>2<span>(<span>|<span>x−3</span>|</span>)</span></span>2</span>≥<span>142</span></span><span><span>|<span>x−3</span>|</span>≥7</span>Step 3: Solve Absolute Value.<span><span>|<span>x−3</span>|</span>≥7</span>We know either<span><span>x−3</span>≥7</span>or<span><span>x−3</span>≤<span>−7</span></span><span><span>x−3</span>≥7</span>(Possibility 1)<span><span><span>x−3</span>+3</span>≥<span>7+3</span></span>(Add 3 to both sides)<span>x≥10</span><span><span>x−3</span>≤<span>−7</span></span>(Possibility 2)<span><span><span>x−3</span>+3</span>≤<span><span>−7</span>+3</span></span>(Add 3 to both sides)<span>x≤<span>−<span>4
the answer is
</span></span></span><span>x≥<span><span>10<span>or </span></span>x</span></span>≤−4
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The answer is 8+1 which is D
I believe that the answer is 4.
4*2=8
4*9=36
:)
Hope this helps!
